Math, asked by krishnasharma8077, 2 months ago

Question numbers 1 to 10 are multiple choice questions of 1 mark each.
Select the correct option.
The point P on x-axis equidistant from the points A(-1,0) and B(5,0) is
(a) (2,0)
(b) (0, 2)
(c) (3,0)
(d) (2, 2)
1.
2.
The co-ordinates of the point which is reflection of point (-3, 5) in x-axis
are
(a) (3,5)
(b) (3,-5)
(c) (-3,-5) (d) (-3,5)
3.
If the point P (6,2) divides the line segment joining A(6,5) and B(4, y) in
the ratio 3:1, then the value of y is
(a) 4
(b) 3
(c) 2
(d) 1:
4.
The sum of exponents of prime factors in the prime-factorisation of 196 is
(a) 3
(b) 4
(C) 5
(d) 2

Answers

Answered by sriunugoud243

Step-by-step explanation:

Since point lies on x-axis, y-coordinate of the point will be zero.

Since point lies on x-axis, y-coordinate of the point will be zero.Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)

Since point lies on x-axis, y-coordinate of the point will be zero.Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)Using section formula:

Since point lies on x-axis, y-coordinate of the point will be zero.Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)Using section formula:x=

Since point lies on x-axis, y-coordinate of the point will be zero.Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)Using section formula:x= 1+1

Since point lies on x-axis, y-coordinate of the point will be zero.Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)Using section formula:x= 1+11×(5)+1×(−1)

Since point lies on x-axis, y-coordinate of the point will be zero.Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)Using section formula:x= 1+11×(5)+1×(−1) or x=2

Since point lies on x-axis, y-coordinate of the point will be zero.Let P(x,0) be on x-axis which is equidistant from A(−1,0) and B(5,0)Using section formula:x= 1+11×(5)+1×(−1) or x=2Thus, the required point is (2,0).

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