Question of 2nd class
A man borrow 8000 and agrees to repay with a total interest of 1360 in 12
monthly instalments. Each instalment being less than the preceding one by ₹40. Find the amount of the first and last instalment.
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Answer:
The amount of money that man borrows is Rs8000 and the interest he has to pay is Rs1360.
The total money he has to pay is,
8000+1360=Rs9360
Since, he has to pay in 12 installments with a difference of 40 in each installment, then, it will form an A.P. where d=−40, n=12 and S
n
=9360.
Therefore,
sn=9360
9360=6(2a−440)
1560=2a−440
2a=2000
a=1000
The last term in A.P. is,
=a+(n−1)d
=1000+(12−1)(−40)
=1000−440
=560
Therefore, the first installment is Rs1000 and the last installment is Rs560.
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