Question

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A circle of center (-3 , -2) passes through the points (0 , -6) and (a , 0). Find a.

Answer 1

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Answer 2

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(x + 3)^2 + (y + 2)^2. = r^2 ···· ··· ··(1) . Since it passes through the point (0, -6) therefore (1) gives 3^2 + 4^2 = r^2 ==> r^2 = 25 . Putting in (1) we get the required equation of the circle as ;

(x + 3)^2 + (y + 2)^2 = 25 ···· ···· ···(2) . Further as the circle also passes through the point (a, 0) ==> (a + 3)^2 + 2^2. = 25 ==> (a + 3) = (+/-)sqrt(21)

which implies a =(-3) +sqrt(21) and

a=(-3) - sqrt(21) .

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