Question

(question of the day)
(physics)

A block of weight 100N is slowly slid up on a smooth incline of inclination 37° by a person.The work done by the person in moving the block through a distance of 2.0 m, if the applied force is

1)parallel to the incline
2)horizontal to the incline

× PLEASE GIVE A PROPER ANSWER. ​

Answer 1

Answer:

Explanation:

A::B

Solution :

W=100N,θ=370,s=2m

Force, F=mgsin370

=100×35=60N

So, work done when the force is parallel to incline,

w=Fscosθ

=60×2×cos00=120'J

In△ABC,AB=2m

AC=hs sin 37^0=1.2m:.Workdo≠whentheforce∈horizontaldirectionw=mgh=100xx1.2=120J`

Answer 2

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