Question

Question of the Day!

Train moves from rest to a speed of 60 m/s in 30 seconds. What is the magnitude of its acceleration?​

Answer 1

Answer:

Step-by-step explanation:

A=v/t

A=60/30

A=2m/s²

Answer 2

✠ Required Solution :

• ❍ Acceleration of train is 2m/s²

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★ Given :

• ➮ Initial velocity of train (u) = 0
• ➮ Final velocity of train (v) = 60m/s
• ➮ Time taken by train (T) = 30sec

★ Need to Find :

• ⪼ Acceleration of the train ?

★ Formula Used Here :

• ⪼ v = u + at

⌬ Where :

• ↠ v = Final velocity
• ↠ u = Initial velocity
• ↠ a = acceleration
• ↠ t = Time taken

❒ Understanding the concept :

➥ For solving this question whe have to apply 1st equation of motion. After putting value in formula we can easily calculate the acceleration of train !

⌬ Putting value in formula :

• ⟶ v = u + at
• ⟶ 60m/s = 0 + a × 30s
• ⟶ 60 = 0 + 30a
• ⟶ 60 = 30a
• ⟶ a = 2 m/s²

❒ Therefore :

•°• Acceleration of train is 2m/s²

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