Math, asked by Anonymous, 11 months ago

QUESTION OF TRIGONOMETIC IDENTITIES

Prove that:
Sec^6theta = tan^6theta + 3tan^2theta× sec^2theta + 1

The question no. 31 in the attachment

A humble plea answer it ,
the correct answer will be surely marked brainliest

Attachments:

Answers

Answered by studymaster45
45

Answer:

Please mark as brainliest!!!!!!!

Attachments:
Answered by RvChaudharY50
63

||✪✪ QUESTION ✪✪||

Prove that:

Sec^6theta = tan^6theta + 3tan^2theta× sec^2theta + 1

|| ✰✰ ANSWER ✰✰ ||

Taking LHS, we get,

sec^6A

→ (sec²A)³

Now, using sec²A = 1 + Tan²A we get,

(1 + Tan²A)³

Now, using (a+b)³ = + + 3ab(a+b) we get,

(1)³ + (Tan²A)³ + 3 * 1 * Tan²A (1 + Tan²A)

Again, using (1+tan²A) = sec²A we get,

→ 1 + Tan^6A + 3Tan²A*sec²A

→ Tan^6A + 3Tan²A*sec²A + 1 = RHS .

Hence Proved .

Similar questions