Question: On an object of mass 1 kg moving along x-axis with constant speed 8m/s, a constant force 2 N is applied in positive y- direction. Find its speed after 4 seconds.
Please explain how to solve the above question. The answer is 8√2m/s.
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Since no force is acting on the object in X direction, it's velocity in X direction will be unchanged.
For Y direction we find the acceleration.
F = MA
A = (2/1) = 2 m/s^2
Now we find the velocity of the object in Y direction
V = U + AT
V = 0 + 2×4 = 8 m/s
So after 4 seconds its velocities in both X and Y direction are 8m/s.
To Find Speed,
Speed = √((Vx)^2+(Vy)^2)
Where Vx is velocity in X direction and By is the velocity in Y direction.
Speed = √(64+64)
Speed = ✓128
Speed = 8✓2 m/s.
For Y direction we find the acceleration.
F = MA
A = (2/1) = 2 m/s^2
Now we find the velocity of the object in Y direction
V = U + AT
V = 0 + 2×4 = 8 m/s
So after 4 seconds its velocities in both X and Y direction are 8m/s.
To Find Speed,
Speed = √((Vx)^2+(Vy)^2)
Where Vx is velocity in X direction and By is the velocity in Y direction.
Speed = √(64+64)
Speed = ✓128
Speed = 8✓2 m/s.
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