Question

Question on @Quora: In hydrogen atom the electron makes 6.6 ×10^15 revolution per second around the nucleus in an orbit of radius 0.5×10^-10 it is equivalent to current nearly?

Answer 1

here is the answer to your question

Answer 2

Given that,

Frequency $f=6.6\times10^{15}\ rev/sec$

Radius $r=0.5\times10^{-10}\ m$

We know that,

Frequency :

The frequency is reciprocal of time.

$f=\dfrac{1}{t}$....(I)

We need to calculate the current

Using formula of current

$I=\dfrac{q}{t}$

$I=q\times\dfrac{1}{t}$

From equation (I)

$I=q\times f$

Where, q = charge of electron

t = time

Put the value into the formula

$I=1.6\times10^{-19}\times6.6\times10^{15}$

$I=0.001\ A$

$I=1\ mA$

Hence, The current is 1 mA.