Question on factorizing expressions
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1.area of the triangle-1/2bh
1/2{x-2*h}=1/2x^2+3/2x-5
1/2[xh-2h]
xh-2h/2
h[x-2/2]=x^2+3x-10/2
h=x^2+3x-10/x-2
when factorized
h=x^2+5x-2x-10
h=(x-2)(x+5)/x-2
h=x+5
1/2{x-2*h}=1/2x^2+3/2x-5
1/2[xh-2h]
xh-2h/2
h[x-2/2]=x^2+3x-10/2
h=x^2+3x-10/x-2
when factorized
h=x^2+5x-2x-10
h=(x-2)(x+5)/x-2
h=x+5
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