Question

Question:
On imparting 10C charge to a conductor
its potential rises by 2 volt. The capacity
of conductor is -
Marks: 2
A 5 F
B 20 F
C 12 F
D 8 F​

Answer 1

Explanation:

make two equation and solve them

Answer 2

Answer:

The capacity of the conductor will be 5 F.

Explanation:

The proportion of a conductor's charge to potential is referred to as the conductor's capacity - C = $\frac{Q}{V}$.

⇒ CV = Q   Let this be referred as A.

Given that:

C = $\frac{Q + 10}{V + 2}$

⇒ CV + 2C = Q + 10 Let this be referred as B.

Now lets do B - A

(CV + 2C = Q + 10) - (CV = Q)

⇒ 2C = 10

C = 5 F

Let's imagine we have a big plate and we positively charge it. There is a limit to how much charge can be applied to the plate because as the charge is applied, the potential of the plate increases, and beyond a certain point, charges begin to leak. A second plate will be drawn toward the side of this one that is farther from the positively charged plate and toward the side that is closest to it if it is placed adjacent to the positively charged plate.

Thus, the voltage across the plates has an inverse relationship with capacity and is directly proportional to the charge stored.