Question

⭐Question :-

On one page of a telephone directory, there were 200 telephone numbers. The frequency distribution of their unit's digits is given in the Above table :-

Out of the numbers on the page, a number is chosen at random. What is the probability that the unit's digit of the chosen number is :-

1. 6?
2. A nonzero multiple of 3?
3. A nonzero even number?
4. An odd number?
5. ABCD is a rhombus and P.


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Answer 1

Here is ur Answer...❤

(i) 0.07

(ii) 0.28

(iii) 0.3

(iv) 0.53

Hope it Helps...❤

Answer 2

Answer:

The probability that the unit's digit of the number:

1) $6$ is $0.07$.

2) A nonzero multiple of $3$ is $0.28$.

3) A nonzero even number is $0.36$.

4) An odd number is $0.53$.

Step-by-step explanation:

Given,

The total frequency of numbers, n(T) = $200$

Units digit =    $0$     $1$      $2$     $3$    $4$     $5$     $6$     $7$     $8$     $9$

Frequency =   $22$   $26$    $22$   $22$   $20$   $10$   $14$   $28$   $16$   $20$

1) The probability that the unit's digit of the number $6$ =?

• Let the event = A
• The frequency whose unit's digit is $6$, n(A) = $14$
• The probability that the unit's digit of the number $6$, P(A):
• $P(A) = \frac{n(A)}{n(T)}$ = $\frac{14}{200}$ = $0.07$.

2) The probability that the unit's digit of the nonzero multiple of $3$ =?

• Let the event = B
• Multiples of $3$ are $3, 6$ and $9$ in the given table.
• The frequency whose unit's digit is a nonzero multiple of $3$, n(B) = $22 + 14 + 20 = 56$
• The probability that the unit's digit of the nonzero multiple of $3$, P(B):
• $P(B) =\frac{n(B)}{n(T)} = \frac{56}{200}$ = $0.28$.

3) The probability that the unit's digit of the nonzero even number =?

• Let the event = C
• Non-zero even numbers are $2, 4, 6, 8.$
• The frequency whose unit's digit is a nonzero even number, n(C) = $22 + 20 + 14 + 16$ = $72$
• The probability that the unit's digit of the nonzero even number, P(C):
• $P(C) = \frac{n(C)}{n(T)}$ = $\frac{72}{200}$ = $0.36$.

4) The probability that the unit's digit of an odd number =?

• Let the event = D
• The odd numbers are $1, 3, 5, 7, 9.$
• The frequency whose unit's digit is an odd number, n(D) =$26+ 22+ 10+ 28+ 20 = 106$
• The probability that the unit's digit of an odd number, P(D):
• $P(D) = \frac{n(D)}{n(T)}$ = $\frac{106}{200}$ = $0.53$.