Question

Question One) 3 brothers share a sum of money. The eldest gets 3/5 of it and the youngest gets 1/10 of it. If the second brother gets $54, how much will the others get?

Question Two) 2/9 of the people in a restaurant are adults. If there are 95 more children than adults, how many customers are there in the restaurant?

Please show steps if you want me to mark you the brainliest.

Answer 1

Answer:

Answer 1

See that the oldest brother has 3/5 of the total, the total comes in 5 portions.

To find the total first:

5/3×108= 180

So the total is $180.

The youngest had 1/10 of the $180:

1/10×180= 18$

So the youngest had $18.

Now the 2nd brother's portion can be found in two ways:-

Alternative 1: Minus the money the first & youngest had

180–108–18= $54

OR

Alternative 2: Find the 2nd brother's portion

1–3/5–1/10= 3/10

Now from the portion, find how much money he has:

3/10×180= $54

~ 1st = $108

~ 2nd = $54

~ 3rd = $18

Answer 2

If there are 2/9 x adults then there are 7/9 x children.

There is a difference of 95 between the two.

5/9 x = 95

x = 9(95)/5 = 171 (Number of adults and children)

Number of children = 7/9 (171) = 133