Question

Question :
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➡️One card is drawn from a well-shuffled deck of 52 cards. Calculate the probability that the card will

(i) be an ace

(ii) not be an ace.

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Answer 1

Answer:

Hope it's helpful for you

Step-by-step explanation:

Well-shuffling ensures equally likely. outcomes.

(i) Card drawn is an ace:

There are 4 aces in a deck.

Let E be the event 'the card is an ace'.

The number of outcomes favourable to E =n(E) = 4

The number of possible outcomes = Total number of cards = n(S) = 52

Therefore, P(E) = n(E)/n(S) = 4/52 = 1/13

(ii) Card drawn is not an aceace:

Let F be the event 'card drawn is not an ace'.

The number of outcomes favourable to the event F = n(F) = 52 - 4 = 48

Therefore, P(F) = n(F)/n(S) = 48/52 = 12/13

#its Sayan✌

Answer 2

Since, there are $52$ Cards to be taken out at random,

Total Outcomes $=52$

(i) We know that there are $4$ Ace cards in a deck, So

Favourable Cases $=4$

Probability $= \dfrac{4}{52} = \dfrac{1}{13}$

(ii) We know that there are $52-4=48$ cards, which are not Ace cards.

Favourable Cases $=48$

Probability $= \dfrac{48}{52} = \dfrac{12}{13}$