Question = One side of a rectangle is 3 cm shorter than the other side. If we increase the length of each side by 1 cm, then the area of the rectangle
will increase
by 18 cm^2. Find the lengths of all sides.
Answers
Answered by
1
Let Length Of the Longer Side = x.
Shorter Side = x-3.
Area = x(x-3) cm².
Increase Length = (x + 1) & (x - 2) cm.
Area Of New Rect. = x(x-3) + 18 = (x+1)(x-2)
= x² - 3x + 18 = x(x-2) +1(x-2)
= x² - 3x + 18 = x² - 2x +x -2.
= x² - 3x + 18 = x² - x -2.
= 2x = 20
= x = 20/2 = 10.
x = 10.
So, Sides Of Rect. are 10 cm. & 7 cm Long.
Shorter Side = x-3.
Area = x(x-3) cm².
Increase Length = (x + 1) & (x - 2) cm.
Area Of New Rect. = x(x-3) + 18 = (x+1)(x-2)
= x² - 3x + 18 = x(x-2) +1(x-2)
= x² - 3x + 18 = x² - 2x +x -2.
= x² - 3x + 18 = x² - x -2.
= 2x = 20
= x = 20/2 = 10.
x = 10.
So, Sides Of Rect. are 10 cm. & 7 cm Long.
ROYALJATT:
its wrong
Answered by
0
let side of rectangle be x then other side will be x-3
then the area will be
A=x*(x-3)
now aac to question new side will be by adding 1
x+1 and x-3+1
⇒ x+1 and x-2
so new area will be A' for new sides
A'=(x+1)(x-2)
now acc to question
A'-A= 18
(x+1)(x-2)-x(x-3)=18
+x-2x-2-+3x=18
x-2x+3x=18
2x=18
x=9 cm
so other side will be 6 cm
then the area will be
A=x*(x-3)
now aac to question new side will be by adding 1
x+1 and x-3+1
⇒ x+1 and x-2
so new area will be A' for new sides
A'=(x+1)(x-2)
now acc to question
A'-A= 18
(x+1)(x-2)-x(x-3)=18
+x-2x-2-+3x=18
x-2x+3x=18
2x=18
x=9 cm
so other side will be 6 cm
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