Question

Question !!

Perimeter of an isosceles triangle is 50 cm one of its side is 24 cm and the other two sides are equal find the area

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Answer 1

Answer:

its ans is that add 50 and 24 with each other and that will be the answer

Answer 2

Answer :

• Area of triangle is 60cm².

Given :-

• Perimeter of an isosceles triangle is 50 cm one of its side is 24 cm and the other two sides are equal.

To Find :-

• Find it's area ?

Solution :-

• Other two equal sides y cm and y cm.

• Using formula,

• Perimeter of ∆ = a + b + c

Where,

• a = first side of ∆
• b = second side of ∆
• c = third side of ∆

We have,

• a = 24 cm
• b = y cm
• c = y cm
• Perimeter of ∆ = 50 cm

• Putting all values in formula,

➻ 50 = 24 + y + y

➻ 50 = 24 + 2y

➻ 50 - 24 = 2y

➻ 26 = 2y

➻ y = 26/2

➻ y = 13

• Hence, other two equal sides of triangle 13 cm and 13 cm.

• Using formula,

• s = (a + b + c)/2

Where,

• s = semi perimeter of ∆
• a = first side of ∆
• b = second side of ∆
• c = third side of ∆

We have,

• a = 24 cm
• b = 13 cm
• c = 13 cm
• s = ?

• Putting all values in formula,

➻ s = (24 + 13 + 13)/2

➻ s = (24 + 26)/2

➻ s = 50/2

➻ s = 25

• Hence, semi perimeter of ∆ (s) is 25 cm.

Now, we have all required values. So, let's find the area of given triangle by using well known formula I.e, heron's formula,

• Using formula,

• A = √[(s(s - a)(s - b)(s - c)]

Where,

• A = area of ∆
• s = semi perimeter of ∆
• a = first side of ∆
• b = second side of ∆
• c = third side of ∆

We have,

• a = 24 cm
• b = 13 cm
• c = 13 cm
• s = 25 cm
• A = ?

• Putting all values in formula,

➻ A = √[(25(25 - 24)(25 - 13)(25 - 13)]

➻ A = √[25(1)(12)(12)]

➻ A = √(25 × 1 × 12 × 12)

➻ A = √(5 × 5 × 12 × 12)

➻ A = 5 × 12

➻ A = 60

• Hence, area of given triangle is 60 cm².

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