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Answer 1

Step-by-step explanation:

side of square = 28 cm.

circle of maximum area is cut out. Therefore, radius of circle must be =

$\frac{28}{2} = 14$

we know that area of the circle is =

$\pi {r}^{2} \\ \pi \times 14 \times 14 \\ 196\pi$

or 607.6

${cm}^{2}$

area of the square is =

${a}^{2} \\ 28 \times 28 \\ 784 {cm}^{2}$

remaining area = (area of square) - ( area of circle)

$\pi {r}^{2} - {a}^{2} \\ 784 - 607.6 \\ 77.4 {cm}^{2}$

Answer 2

Step-by-step-Explanation:

Given:Square of side 28 cm.

To find: Maximum circle to be cut from the square cardboard.

Solution:

The diameter of circle must be equal to side of the square,so that circle will be maximum.

Diameter of circle=28 cm

Hence radius of circle r= 14 cm

Area of circle = π×r²

$= \frac{22}{7} \times 14 \times 14 \\ \\ = 616 \: {cm}^{2}$

The area if cardboard left out,after removing circle:

Area of square-Area of Circle

$= ( {28)}^{2} - 616 \\ \\ = 784 - 616 \\ \\ = 168 \: {cm}^{2}$

Thus,

Area of largest circle =616 cm²

Area if left out card board= 168 cm².

Hope it helps you.

To learn more on brainly:

find the area of circle circumscribing an equilateral triangle of side 15 CM( take π=3.14)

https://brainly.in/question/5536791