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plz ans i need it :)
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Let the number be
(3x)x
remember These are just digits not in multiplication
Initial number is 3x*10+x
=31x
When digits reversed , number becomes
x(3x)
Value= x*10+3x= 13 x
Given in question
31x-36=13x
Solving we get x=2
Thus original number is (3*2)2
=62
Mark brainliest if you likw
(3x)x
remember These are just digits not in multiplication
Initial number is 3x*10+x
=31x
When digits reversed , number becomes
x(3x)
Value= x*10+3x= 13 x
Given in question
31x-36=13x
Solving we get x=2
Thus original number is (3*2)2
=62
Mark brainliest if you likw
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