Question:
Point P (2, -7) is the centre
of a circle with radius 13 unit, PT is perpendicular to chord AB and T = (-2,-4);
Calculate the length of:
(i) AT
(ii) AB.
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Answer:
PT = √{(2+2)^2 + (-7+4)^2} = √25 = 5
AT^2 = 13^2- 5^2 = 169-25=144
AT = 12
AB = 24Ans
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