Question

Question༉

Praveen wanted to make a temporary shelter for her car, by making a box – like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5m, with base dimensions 4m×3m?​

Answer 1

Step-by-step explanation:

Dimension of the non-like structure = 4m×3m×2.5m

Tarpaulin only required for all the

for sides and top.

Thus Tarpaulin required = 2(l+b)×h+lb

=[2(4+3)×2.5+4×3]m^2

=[35+12]m^2

=47m^2

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Answer 2

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