Math, asked by Vamprixussa, 1 year ago

║⊕QUESTION⊕║
.
prove
sin^{2} [\frac{\pi }{8} + \frac{Ф}{2} ] - sin^{2} [\frac{\pi}{8} - \frac{Ф}{2} ] = \frac{1}{\sqrt{2} } sin Ф

Answers

Answered by OLegion
1

Answer:

Please find the answer in the attachment..

Hope it helps...

Regards;

Leukonov/Olegion

Attachments:
Answered by raja2511919
1

Answer:

this is your solution for the following information

Attachments:
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