Question

Question question answer
question answer
question answer​

Answer 1

Answer:

Area of ∆ PQR=1/2 × RQ ×PS

Area of ∆ PQR = 1/2 × PR × QT

1/2 × RQ ×PS = 1/2 × PR × QT

RQ ×PS =PR × QT

6 × 6 = 12 × QT

QT =( 6×6/12 ) 1

QT = 3