Question

✧ Question ✧✧✦ ➠ ᴅᴏɴᴛ sᴘᴀᴍ⚠️ If sinx+siny+sinz=3. Find the value of cos^3x+cos^3y+cos^3z.​

Answer 1

Answer:

0

Step-by-step explanation:

sinx+siny+sinz=3

maximum value of sin is 1

so sinx=siny=sinz=1

x=y=z=90°

so cosx=cosy=cosz=0

cos^3x+cos^3y+cos^3z

=0+0+0

=0

Answer 2

Answer:

Here is your answer buddy,

Step-by-step explanation:

Question,

If sinx+siny+sinz=3. Find the value of cos^3x+cos^3y+cos^3z.

Answer,

Point that we should know,

• $range\: of \: sin\: is\: [ - 1, 1 ]$

• $Sin\: \: 90° \: = \: 1$

• $Cos \: \: 90°\: =\: 0$

Answer,

Given,

$sin\: x \: + \: sin \: y \: + \: sin \: z \: = \: 3$

$As\: sin\: value\: lies\: between\: - 1 \: and\: 1\: ,$

$We\: can\: see\: that \: there\: is \: one\: possibility \:$

$THAT \: \: IS,$

$\: 1\: \: +\: \: 1 \: \: +\: \: 1 \: \: =\: \: 3$

SO, ON COMPARISON

$Sin\: X \: =\: 1\:$

$Sin\: Y \: =\: 1$

$Sin\: Z \: =\: 1$

We know that Sin 90° = 1

$Sin\: X \: =\: Sin 90° \:$

$Sin\: Y \: =\: Sin 90°$

$Sin\: Z \: =\: Sin 90°$

On Comparing,

X=90° ,Y=90° ,Z=90°

Value of cos^3x+cos^3y+cos^3z is,

${(cos \: x)}^{3} + {(cos \: y)}^{3} + {(cos \: z)}^{3}$

${(cos \: 90°)}^{3} \: + \: {(cos \: 90°)}^{3}\: + \: {(cos \: 90°)}^{3}$

${(0)}^{3} \: + \: {(0)}^{3} \: + \: {(0)}^{3}$

$0 \: \: +\: \: 0 \: \: + \: \: 0$

$0$

The value of cos^3x+cos^3y+cos^3z is 0

Have a good day ❤️

Sorry buddy I don't know Hindi to answer your remaining question ❤️