Physics, asked by shreyamitra822, 3 days ago

✦✧✧ Question ✧✧✦ ➠ ᴅᴏɴᴛ sᴘᴀᴍ⚠️ The kinetic energy of an object of mass m, moving with a velocity of 5 m/s is 25 J. What will be its kinetic energy when its speed is doubled? it is given here doubled not tripled​

Answers

Answered by PopularStar
153

Given,

velocity of object, \bf{v=5\: m/s}

As kinetic energy of the object is,

 \bf{E_k =25\:J}\\\\

\bf\red{ E_k=\dfrac{1}{2}{mv^2}}\\\\

 \implies 25 = \dfrac{1}{2}\times m\times 5^2\\\\

 \implies m = \dfrac{50}{25}\\\\

 \large \implies \bf \pink{ m = 2\: kg}\\\\

Now,

When the velocity is Doubled,

so new velocity is 10 m/s

Hence

 E_k=\dfrac{1}{2}\times 2\times 10^2\\\\

 = \dfrac{200}{2}\\\\

 \large \implies \bf \pink{ E_k = 100\: Joule}\\\\

Answered by SparklingBoy
148

 \large \dag Question :-

The kinetic energy of an object of mass m, moving with a velocity of 5 m/s is 25 J. What will be its kinetic energy when its speed is doubled ?

 \large \dag Answer :-

\red\dashrightarrow\underline{\underline{\sf  \green{Kinetic\:Energy   \:  is \:  100\: Joule}} }\\

 \large \dag Step by step Explanation :-

Here we have given that,

  • Velocity of Object = v = 5 m/s

  • Kinetic Energy of Object = K.E. = 25 J

  • Mass of Object = m

We Know that Kinetic energy is ;

 \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{   \blue{  K.E. =  \frac{1}{2} mv {}^{2} }}}} \\

Putting Values we get ,

:\longmapsto \rm 25 =  \frac{1}{2}  \times m \times  {5}^{2}  \\

:\longmapsto \rm 25 =  \frac{25}{2}  \times m \\

:\longmapsto \rm m = \cancel{25}  \times   \frac{2}{ \cancel{25}}  \\

\purple{ \large :\longmapsto  \underline {\boxed{{\bf m= 2 \: kg} }}}

When it's speed is doubled :-

:\longmapsto \rm Velocity = v'  = 2 \times 5 \\

\pink{ \large :\longmapsto  \underline {\underline{{\bf v'  = 10 \: m/s} }}}

Now Applying Formula if Kinetic Energy ;

:\longmapsto \rm K.E.' =  \frac{1}{2}  \times m \times ( {v'})^{2}  \\

:\longmapsto \rm K.E.' =  \frac{1}{\cancel2}  \times  \cancel2 \times  {10}^{2}  \\

:\longmapsto \rm K.E.' = 10 \times 10 \\

\purple{ \large :\longmapsto  \underline {\boxed{{\bf K.E.' = 100 \: J} }}}

Therefore,

\large\underline{\pink{\underline{\frak{\pmb{Kinetic  \: Energ \text y \:  is   \: 100 \: Joule}}}}}

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