⇢Question:-
sin²5 + sin²10 + sin²15 + ••• + sin²85° + sin²(90°) =?
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Explanation:
sin²(5) + sin²(10) + sin²(15) + ... + sin²(90 - 15) + sin²(90 - 10) + sin²(90 - 5) + sin²(90°)
As we know that sin(90 - theta) = cos theta
Therefore, sin²5 + sin²10 + sin²15 + ... + cos²15 + cos²10 + cos²5 + sin²90
Now we all know that sin²a + cos²a = 1
Therefore sin²5 + cos²5 = 1
Similarly, we will simplify the expressions.
But sin²90° and sin²45° would be left so we will add their individual values.
sin²90 = 1 and sin²45 = 1/2
So the expression would become 1*8 + 1 + 1/2
= 19/2
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