Question

Question:- Solve dy/dx + x/1-x^2y = x√y .​

Answer 1

Answer:

y = k.(1+x^3)^1/3

Step-by-step explanation:

(1+x^3).dy/dx= x^2.y

or (1/y).dy = x^2/(1+x^3).dx

or log y = (1/3). 3x^2/(1+x^3).dx

or log y = (1/3)log (1+x^3) +log k.

or log y = log (1+x^3)^1/3. k.

or y = k.(1+x^3)^1/3