Math, asked by rhb90mm, 7 months ago

Question; Solve each equation: PRELIMINARIES (A) 2x + 8 = x − 4 (B) 3r + 2 − 5(r + 1) = 6r + 4 (C) x 2sequer + 5x + 6 = 0

Answers

Answered by Deepeshraj24102007
1

Answer:

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Step-by-step explanation:

a) 2x+8=x-4

2x+x=8-4

3x=4

x=4/3

b) 3r+2-5(r+1)=6r+4

Reorder the terms:

3r + 2 + -5(1 + r) = 6r + 4

3r + 2 + (1 * -5 + r * -5) = 6r + 4

3r + 2 + (-5 + -5r) = 6r + 4

Reorder the terms:

2 + -5 + 3r + -5r = 6r + 4

Combine like terms: 2 + -5 = -3

-3 + 3r + -5r = 6r + 4

Combine like terms: 3r + -5r = -2r

-3 + -2r = 6r + 4

Reorder the terms:

-3 + -2r = 4 + 6r

Solving

-3 + -2r = 4 + 6r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-6r' to each side of the equation.

-3 + -2r + -6r = 4 + 6r + -6r

Combine like terms: -2r + -6r = -8r

-3 + -8r = 4 + 6r + -6r

Combine like terms: 6r + -6r = 0

-3 + -8r = 4 + 0

-3 + -8r = 4

Add '3' to each side of the equation.

-3 + 3 + -8r = 4 + 3

Combine like terms: -3 + 3 = 0

0 + -8r = 4 + 3

-8r = 4 + 3

Combine like terms: 4 + 3 = 7

-8r = 7

Divide each side by '-8'.

r = -0.875

Simplifying

r = -0.875

c)

The solutions are

x

=

2

,

x

=

3

Explanation:

x

2

5

x

+

6

=

0

Here we can first factorise the expression and then find the solution:

Factorising by splitting middle term

x

2

2

x

3

x

+

6

=

0

x

(

x

2

)

3

(

x

2

)

=

0

(

x

2

)

(

x

3 )

=

0

Equating the two factors with zero to obtain solutions:

x

2

=

0

,

x

=

2

x

3

=

0

,

x

=

3

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