Question

Question: solve this question​

Answer 1

Step-by-step explanation:

In Triangle AOB and Triangle BOC

AB=AC (given)

angle ABO=angle CBO(given)

OB=OB (common)

THEREFORE

️AOB=~️BOC (by SAS)

angle OAB=angle OCB (by congruent Parts criteria of Triangle)

since Angle DAB +angle OAB=180° (linear pair)

angle DAB =180-angle OAB

similarly angle ECB= 180-angle OCB

So, ang.DAB = ang.ECB (from above ang.ABO= ang.CBO)

Hence Verified...

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