Math, asked by anshpriya727, 4 months ago

Question:
Subtract the sum of (a²+ 5ab+b²) and
(2a²-4ab+5b²) from the sum of
( 5a² - 7ab+4ab²) and (7a²-2ab+3b²)​

Answers

Answered by nariseamalavathi
1

Step-by-step explanation:

the sum of (a²+ 5ab+b²) and (2a²-4ab+5b²)

a²+5ab+b²+2a²-4ab+5b²

3a²+ab+6b²

the sum of ( 5a² - 7ab+4ab²) and (7a²-2ab+3b²)

5a²-7ab+4ab²+7a²-2ab+3b²

=12a²-9ab+4ab²+3b²

Question:

Subtract the sum of (a²+ 5ab+b²) and

(2a²-4ab+5b²) from the sum of

( 5a² - 7ab+4ab²) and (7a²-2ab+3b²)

=12a²-9ab+4ab²+3b²-(3a²+ab+6b²)

=12a²-9ab+4ab²+3b²-3a²-ab-6b²

=9a²-10ab+4ab²-3b²

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