Math, asked by Anonymous, 1 year ago

Question = Supriya started working in an office in 1995 where her annual income is 5000 and received an increase of 200 rupees each year. In which year did her salary reach 7000 ?


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Answers

Answered by CaptainBrainly
18
Hey Bro !!

Thanks for the question.

Given,

Supriya started working from 1995.

Starting Salary = 5000

Increase in salary each year = 200

Let, a = 5000 and d = 200

5000, 5200, 5400......7000 are in AP.

an = 7000

a + ( n - 1 ) d = 7000

5000 + ( n - 1 )200 = 7000

5000 + 200n - 200 = 7000

4800 + 200n = 7000

200n = 7000 - 4800

200n = 2200

n = 2200/200

n = 11

Therefore, her salary reaches 7000 in 2006

TooFree: 1995 - Rs 5000 / 1996 - Rs 5200 / 1997 - Rs5400 / 1998- Rs 5600 / 2000 - Rs 5800/ 2001 - Rs 6000 / 2002- Rs 6200 / 2003 - Rs 6400 / 2004- Rs 6600 / 2005- Rs 6800 /2006- Rs 7000
CaptainBrainly: we should count 1995 also
Steph0303: Yup 1995 is counted
TooFree: She did not get an increment upon starting work ... she worked a year before she gets her increment.
CaptainBrainly: Oh okay let me edit
Steph0303: Cool :)
CaptainBrainly: Guys done thanks !
TooFree: @Captain .. would you be kind enough to give me an edit for my answer? Made a typo
CaptainBrainly: ok
judo22: hello do you reading class 12
Answered by TooFree
19

General equation for an AP:

 a_n = a_1 +(n - 1)d


Starting income = a1 = Rs 5000 (Given)

difference = d = Rs 200 (Given)

Final amount = Rs 7000 (Given)


Find the number of years needed (Find n):

7000 = 5000 + (n - 1) (200)

7000 = 5000 + 200n - 200

7000 = 4800 + 200n

200n = 7000 - 4800

200n = 2200

n = 11


Find the year that her salary will reach Rs 7000:

1995 + 11 years = 2006


Answer: She will have a salary of Rs 7000 in year 2006

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