Math, asked by Anonymous, 30 days ago

Question:_________
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\begin{gathered} \: if \: \frac{3}{5} times \: a \: number \: taken \: \\ away \: from16 \: the \: result \: is \\ \\ the \: number \: itself \\ \: what \: is \: the \: number\end{gathered}









answer please​

Answers

Answered by tennetiraj86
60

Step-by-step explanation:

Given :-

If 3/5 times a number taken away from 16 then the result is the number itself.

To find:-

Find the number?

Solution:-

Let the number be X

3/5 times the number= (3/5)×X

=>3X/5

If 3/5 times a number taken away from 16 then

the result = 16-(3X/5)

According to the given problem

If 3/5 times a number taken away from 16 then the result is the number itself.

=> 16-(3X/5) = X

=>16 = X +(3X/5)

=>16 = (5X+3X)/5

=>16 = 8X/5

=>8X/5= 16

=>8X=16×5

=>8X=80

=>X=80/8

=>X=10

Therefore,X = 10

Answer:-

The required number = 10 for the given problem

Check:-

The number = 10

3/5 times the number = (3/5)×10

=>30/5

=>6

If taken aways 6 from 16

=>16-6

=>10

=The given number

Verified the given relations.

Answered by Anonymous
225

Your answer...

=) 3x-5=16

=) 3x-5=16=)3x=16+5

=) 3x-5=16=)3x=16+5=)3x=21

=) 3x-5=16=)3x=16+5=)3x=21=)x=21/3

=) 3x-5=16=)3x=16+5=)3x=21=)x=21/3=)x=7

Hope it helps

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