Question:_________
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![\begin{gathered} \: if \: \frac{3}{5} times \: a \: number \: taken \: \\ away \: from16 \: the \: result \: is \\ \\ the \: number \: itself \\ \: what \: is \: the \: number\end{gathered} \begin{gathered} \: if \: \frac{3}{5} times \: a \: number \: taken \: \\ away \: from16 \: the \: result \: is \\ \\ the \: number \: itself \\ \: what \: is \: the \: number\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D+%5C%3A+if+%5C%3A+%5Cfrac%7B3%7D%7B5%7D+times+%5C%3A+a+%5C%3A+number+%5C%3A+taken+%5C%3A+%5C%5C+away+%5C%3A+from16+%5C%3A+the+%5C%3A+result+%5C%3A+is+%5C%5C+%5C%5C+the+%5C%3A+number+%5C%3A+itself+%5C%5C+%5C%3A+what+%5C%3A+is+%5C%3A+the+%5C%3A+number%5Cend%7Bgathered%7D+)
answer please
Answers
Step-by-step explanation:
Given :-
If 3/5 times a number taken away from 16 then the result is the number itself.
To find:-
Find the number?
Solution:-
Let the number be X
3/5 times the number= (3/5)×X
=>3X/5
If 3/5 times a number taken away from 16 then
the result = 16-(3X/5)
According to the given problem
If 3/5 times a number taken away from 16 then the result is the number itself.
=> 16-(3X/5) = X
=>16 = X +(3X/5)
=>16 = (5X+3X)/5
=>16 = 8X/5
=>8X/5= 16
=>8X=16×5
=>8X=80
=>X=80/8
=>X=10
Therefore,X = 10
Answer:-
The required number = 10 for the given problem
Check:-
The number = 10
3/5 times the number = (3/5)×10
=>30/5
=>6
If taken aways 6 from 16
=>16-6
=>10
=The given number
Verified the given relations.
Your answer...
=) 3x-5=16
=) 3x-5=16=)3x=16+5
=) 3x-5=16=)3x=16+5=)3x=21
=) 3x-5=16=)3x=16+5=)3x=21=)x=21/3
=) 3x-5=16=)3x=16+5=)3x=21=)x=21/3=)x=7
Hope it helps ✌