Question

❏ QUESTION

$\bf Find \: the \: value \: of \: \sin - \bf: {1} \\ \sin\ \frac{2 \pi}{3}$

TOPIC-:
TRIGNOMETRY
CLASS 12

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Answer 1

Step-by-step explanation:

We have,

$\sin^{ - 1} \bigg \{ \sin \bigg( \frac{2\pi}{3} \bigg) \bigg \}$

$= \sin^{ - 1} \bigg \{ \sin \bigg( \pi - \frac{\pi}{3} \bigg) \bigg \}$

$= \sin^{ - 1} \bigg \{ \sin \bigg( \frac{\pi}{3} \bigg) \bigg \}$

$= \frac{\pi}{3}$

Answer 2

Answer:

your answer is above

hope it helped