Math, asked by Anonymous, 4 months ago

Question :-

\sf{ {x}^{2}} + x + 11 is a prime number. Which of the following is invalid value of x?
a) 8
b) 5
c) 12
d) 10

Please give Answer with explanations !!

Answers

Answered by raushan7393
10

Answer:

10

Step-by-step explanation:

10 is right ans because after putting in equation value of x = 10

10²+10+11 = 121 that's not be prime number so,

10 is right ans

Answered by Anonymous
0

Answer:

Given :-

x² + x + 11 is a prime number

To Find :-

Invalid value of x from the given options

Solution :-

→ Let's solve putting the value of ' x ' in every option to find the invalid value .

★ Option ( a ) ' 8 ' ★

→ Let's put the value of ' x ' as 8

\sf \leadsto 8^{2} + 8 + 11⇝8

2

+8+11

\sf \leadsto 64 + 8 + 11⇝64+8+11

\sf \leadsto 83⇝83

→ Here , 83 is a prime number . So, it is not the invalid option .

_________

★ Option ( b ) ' 5 ' ★

→ Let's put the value of ' x ' as 5

\sf \leadsto 5^{2} + 5 + 11⇝5

2

+5+11

\sf \leadsto 25 + 5 + 11⇝25+5+11

\sf \leadsto 41⇝41

→ Here , 41 is a prime number . So , it is not the invalid option .

__________

★ Option ( c ) ' 12 ' ★

→ Let's put the value of ' x ' as 12

\sf \leadsto 12^{2} + 12 + 11⇝12

2

+12+11

\sf \leadsto 144 + 12 + 11⇝144+12+11

\sf \leadsto 167⇝167

→ Here , 167 is a prime number . So , it is not the invalid option .

_________

★ Option ( d ) ' 10 ' ★

\sf \leadsto 10^{2} + 10 + 11⇝10

2

+10+11

\sf \leadsto 100 + 10 + 11⇝100+10+11

\sf \leadsto 121⇝121

→ Here , 121 is not a prime number as it is divisible by 11 . So , it is the invalid option .

∴ 10 is the value which is invalid for x² + x + 11 = Prime no.

( Option d )

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