Question

Question!
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A 1.0 kg hammer with a velocity of 50 m/s strikes a 200 g iron nail driving it into a block of wood. If half of the energy of the hammer goes into heating the nail, what will be rise in its temperature? (Specific heat capacity of iron = 419J/kg°C)​

Thank you :) ​

Answer 1

Answer:

The answer is 14.916°C

Explanation:

We know that

Energy = msΔФ

Here energy is the kinetic energy.

∴$\frac{1}{2} m(hammer)v^{2} = m(nail)s$ΔФ

⇒ΔФ = $\frac{m(hammer)v^{2} }{m(nail)*s(iron)}$

⇒ΔФ=$\frac{50^{2} }{2*02*419}$

⇒ ΔФ = 14.916°C