Question

Question:-

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A 12 cm rod is held between a flashlight and a wall as shown. Find the length of the shadow on the wall if the rod is 45 cm from the wall and 15 cm from the light. ​

Answer 1

Answer: 48 cm

Step-by-step explanation:

❍ Given :-

• 12 cm of rod is held between a flashlight and a wall (in the figure)

❍ To Find :-

• Length of the shadow on the wall if the rod is 45 cm from the wall and 15 cm from the light

❍ Solution :-

In △ADM and △ABF

⇒ ∠DAM = ∠BAF (Common)

⇒ ∠DMA = ∠BFM (Corresponding angles)

∴ △ADM∼△ABF (By AA Similarity)

$→ \sf \dfrac{AD}{AB} = \dfrac{DM}{BF} = \dfrac{AM}{AF} \: or \: \dfrac{DM}{BF} = \dfrac{AM}{AF}$

$→ \sf \dfrac{6}{BF} = \dfrac{15}{60}$

$→ \sf BF = \dfrac{\cancel{60} \times 6}{\cancel{15}}$

$→ \sf BF = 6 \times 4$

$→ \sf \fbox{BF = 24}$

∴ BC = BF + FC = 2BF = 2 × 24 = 48 (∵ CF = BF)

Therefore, length of the shadow on the wall if the rod is 45 cm from the wall and 15 cm from the light is 48 cm.

Answer 2

Answer:

48cm

is it right ✅ pls tell