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The cross product of 2 vectors is calculated with the determinant
#| (veci,vecj,veck), (d,e,f), (g,h,i) | #
where #veca=〈d,e,f〉# and #vecb=〈g,h,i〉# are the 2 vectors
Here, we have #veca=〈2,-3,4〉# and #vecb=〈1,1,-7〉#
Therefore,
#| (veci,vecj,veck), (2,-3,4), (1,1,-7) | #
#=veci| (-3,4), (1,-7) | -vecj| (2,4), (1,-7) | +veck| (2,-3), (1,1) | #
#=veci((-3)*(-7)-(4)*(1))-vecj((2)*(-7)-(4)*(1))+veck((2)*(1)-(-3)*(1))#
#=〈17,18,5〉=vecc#
Verification by doing 2 dot products
#〈17,18,5〉.〈2,-3,4〉=(17)*(2)+(18)*(-3)+(5)*(4)=0#
#〈17,18,5〉.〈1,1,-7〉=(17)*(1)+(18)*(1)+(5)*(-7)=0#
So,
#vecc# is perpendicular to #veca# and #vecb#
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