Question

Question

The amount of heat needed to melt 2 kg of ice at its melting point, when latent heat of ice is 80 cal/g.is
(1 cal = 4.184 J).
a.40×10^5J
b. 6.7 x 10^5 J
C.3.35×10^5J
3.35 x 10^5 J
d. 1.675 x 10^5 ​

Answer 1

Answer:

if it requires 80 cal/g

then energy needed for 2kg = 80×2000 = 160000 calories or

1 calory = 4.1 j

then.

E = 160000×4.1 = 656000 j = 6.56×10^5 j answer

hope it helps ......

Answer 2

Answer:

Latent heat of fusion of ice : It is defined as the amount of heat energy released or absorbed when solid ice changes to liquid at atmospheric pressure at its melting point. Therefore, the heat required to melt 2 g of ice is 160 cal.

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