Question

Question : The area of rectangular field in 7200 sq mrt. Its length 80 meter then find :
i) Breadth of Rectangle
ii) Perimeter
iii) Veified that your answer is correct

KOI TOH bHai HelP krDo @_@

Answer 1

Answer:

As the area of the rectangular field is 7200sq mrt

length=80m

Step-by-step explanation:

Area of a rectangle =lb

as length *breadth=7200

80*b=7200

b=7200/80

b=90m

There fore the breadth =90m

2)perimeter of a rectangle =2(l+b)

L=80

B=90

2(80+90)

2*170=340m

perimeter of a tectangke 340 meter

HOPE IT HEKPS YOU

MARK ME AS BRAINLIST PLZ

FOLLOW ME

Answer 2

Given,

• The Area of Rectangular Filed = 7200 m²
• Length of Rectangular filed = 80 m

To Find,

• Breadth of Rectangle
• Perimeter of Rectangle
• Verified Answer also

Solution :

$\underline{\underline{\bold{First \ Case - (i)}}}$

$\longrightarrow \underline{\sf{\pink{According \ to \ the \ Question :}}}$

$\star \sf{Length \ of \ Rectangle = 80 m}$

$\star \sf{The \ Breadth \ of \ Rectangle = \ ? }$

$\boxed{\sf{\red{Therefore, \ We \ Know \ that :}}}$

$\implies \sf{Area \ of \ Rectangle = \sf{\purple{(Length \ \times \ Breadth) }}}$

$\implies \sf{Length \ \times \ Breadth = 7200 m^{2}}$

$\implies \sf{80 \ \times Breadth = 7200}$

$\implies \sf{Breadth = \dfrac{7200}{80}}$

$\implies \underline{\boxed{\sf{\red{Breadth = 90m}}}}$

$\underline{\underline{\bold{Second \ Case - (ii)}}}$

$\longrightarrow \underline{\sf{\pink{According \ to \ the \ Question :}}}$

$\boxed{\sf{We \ Know \ that :}}$

$\implies \sf{Perimeter \ of \ Rectangle = \sf{\red{2(Length + Breadth)}}}$

$\implies \sf{Perimeter \ of \ Rectangle = 2(80 + 90)}$

$\implies \sf{Perimeter \ of \ Rectangle = 2(170)}$

$\implies \underline{\boxed{\sf{\red{Perimeter \ of \ Perimeter = 340}}}}$

$\underline{\underline{\bold{Third \ Case - (iii)}}}$

$\longrightarrow \underline{\sf{\pink{According \ to \ the \ Question :}}}$

$\boxed{\large{\sf{Verification :}}}$

$\implies \sf{Area \ of \ Rectangle = (Length \ \times \ breadth)}$

$\implies \sf{7200 = Length \ \times \ Breadth}$

$\implies \sf{7200 = 80 \times 90}$

$\implies \sf{7200 = 7200}$

Hence Verified

$\rule{200}2$