Question

Question
The de-Broglie wavelength associated with
electrons revolving round the nucleus in a
hydrogen atom in the ground state will be
A 3.3 Å
B
1.3 å
C 6.6 Å
D
20 Å​

Answer 1

Answer:

mvr=  nh /2π,    n=1

​ 2πr= h/mv

we know wavelength =h /mv

therefore 2πr= wavelength

and r= 0.529 °A

so wavelength= 2π × 0.529

                         3.3 °A