Question

Question
The diagonals of parallelogram are represented by x = 21-j+k and x = 1+1 – zË The area of
the parallelogram is
sq unit
c esq unit
d V35 sq unit​

Answer 1

Answer:

Here a=3i+j−2k,b=i−3j+4k

Thus a×b= i31j1−3k−24

∣=−2i−14j−10k=−2(i+7j+5k)

Hence area

of parallelogram 

=21∣a×b∣=53