QUESTION :
The elevation of the top of a temple from a point A situated in south is 45° and B is a point to the west of the point A. Also if the elevation of the top of the temple from B is 15° and AB = 2a, then find the height of the temple.
Help _!!
Don't spam __!!
Answers
Answered by
1
Answer:
In ΔADC
tan30
o
=
AC
DC
3
1
=
d
h
........(1)
d=
3
h
→d=
3
×10
3
=30m
In ΔBCD
tan60
o
=
BC
DC
3
=
d−20
h
.......(2)
on solving equation (1) & (2)
3
=
3
h−20
h
⇒3h−20
3
=h
2h=20
3
h=10
3
m
height of tower.
Answered by
2
Answer:
In ΔADC
tan30o=ACDC
31=dh (1)
d=3h
→d=3×103
=30m
In ΔBCD
tan60o=BCDC
3=d−20h
on solving equation (1) & (2)
3=3h−20h
⇒3h−203=h
2h=203
h=103m
height of tower.
Similar questions