Question

Question:-
The length and the breadth of a rectangular field are in the ratio 5 : 3. If its perimeter is 128 m, find the dimensions of the field.





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Answer 1

QUESTION:- The length and the breadth of a rectangular field are in the ratio 5 : 3. If its perimeter is 128 m, find the dimensions of the field.

ANSWER:- Ratios = 5:3 (5x , 3x)

Perimeter=128

Formula= 2( l + b)

so,

$2(5x + 3x) = 128 \\ \\ 10x + 6x = 128 \\ \\ 16x = 128 \\ \\ x = \frac{128}{16} \\ \\ x = 8 \\ \\ now \: \: \\ \\ 5x = 5(8) = 40 \: \: cm \\ \\ 3(8) = 24 \: \: cm \:$

HOPE IT HELPS

MARK BRAINLIEST PLS

Answer 2

Given

• Length and the Breadth = 5:3
• Perimeter is 128 m

Explanation

Let the Length and Breadth of the Rectangular field be 5x and 3x Respectively.

We also Know that:-

$\maltese {\pmb{\boxed{\sf{ Perimeter_{(Rectangle)} = 2(l+b) }}}} \\ \\ \\ \colon\implies{\sf{ 128 = 2(5x+3x) }} \\ \\ \\ \colon\implies{\sf{ 128 = 2(8x) }} \\ \\ \\ \colon\implies{\sf{ 128 = 2 \times 8x }} \\ \\ \\ \colon\implies{\sf{ \cancel{128} = \cancel{16} x }} \\ \\ \\ \colon\implies{\sf{ x = 8 }}$

Hence,

• Length = 5x = 5×8 = 40 metres
• Breadth = 3x = 3×8 = 24 metres

$\\ \maltese \ {\large{\pmb{\underline{\sf{ Verification: }}}}} \\ \\ \\ \colon\implies{\sf{ 128 = 2(5 \times 8+3 \times 8) }} \\ \\ \\ \colon\implies{\sf{ 128 = 2(40+24) }} \\ \\ \\ \colon\implies{\sf{ 128 = 2(64) }} \\ \\ \\ \colon\implies{\sf{ 128 = 128 }} \\ \\ \\ \colon\implies{\large{\pmb{\sf\purple{ LHS = RHS }}}}$