Question

Question:-

The measure of one of the angles of a triangle is thrice the measure of it's smallest angle and the measure of the other angle is five times the measure of it's smallest angle. Find the measure of the three angles.

To Find:-

Find the measures of the three angles.

Given:-

The measure of one of the angles of a triangle is thrice the measure of it's smallest angle and the measure of the other angle is five times the measure of it's smallest angle.

Solution:-

Let the measures of the smallest angle be " x "

The second angle be " 3x "

The third angle be " 5x "

We know that:-

Sum of three angles of a traingle is 180°

\tt\implies \: x + 3x + 5x = 180⟹x+3x+5x=180

\tt\implies \: 9x = 180⟹9x=180

\tt\implies \: x = \cancel\dfrac { 180 } { 9 }⟹x=9180​​

\tt\implies \: x = 20⟹x=20

Hence ,

First angle is 20°

Second angle is 3x = 60°

Third angle is 5x = 100°​

Answer 1

$\huge \mathfrak \red{Answer}$

What uh wants to know ...?

(report my all que plz )

Answer 2

Answer:

Another angle is thrice the measure of the smallest angle. ∴ The measures of the remaining two angles are 2x° and 3x°. The measures of the three angles of the triangle are 30° , 60° and 90°.

Let the smallest angle be x

Given that one angle is twice the smallest angle. Therefore, the angle measure is 2x

Given that other angle is thrice the smallest angle. Therefore, the angle measure is 3x

We know that sum of the angles in a triangle is 180

0

Therefore, x+2x+3x=180

⟹6x=180

⟹x=30

0

Therefore, the smallest angle measure is 30

0

and

the other angle measures are 60

0

,90

0