Math, asked by BrainlyTerracota, 1 month ago

Question :

the numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction.​

Answers

Answered by beenamanu
3

Answer:

Answer is attached here.

Attachments:
Answered by CopyThat
13

Step-by-step explanation:

Given:

The numerator of a certain fraction is 8 less than the denominator.

If 3 is added to the numerator and 3 is subtracted from the denominator.

The fraction becomes 3/4.

To find:

The original fraction.

Solution:

Let the numerator of the fraction be:

  • x

Then, the denominator will become:

  • x + 8

The original fraction will be:

  • x/x + 8

As per the conditions:

› x + 3/x + 8 - 3

› x + 3/x + 5 = 3/4

› 4(x + 3) = 3(x + 5)

› 4x + 12 = 3x + 15

› 4x - 3x = 15 - 12

› x = 3

Numerator will be:

  • x = 3

Denominator will become:

  • x + 8 = 11

The original fraction will be:

  • x/x + 8
  • 3/3 + 8
  • 3/11

The original fraction is 3/11.

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