Question The prism of refracting angel 60 and meup =1.5 has angel of refraction 25 at first face. Angel of incidence at second face is
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Explanation:
The ray will not emerge out of his prism
We have, δ=(μ−1)A
=(1.5−1)×90
=0.5×90
=45
o
Now, δ=(i
1
+i
2
)−A
∴i
2
=δ−i
1
+A
=45−30+90
o
=105
o
Angle of emergence has inclination with second surface
=90−105
=−15
This shows that light ray will not emerge out of the prism.
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