Question

question :-

The radius of the sphere is increased by 200 % . The volume of the corresponding sphere is increased by?​

Answer 1

$2600\%$

Step-by-step explanation:

Let the radius of the sphere be r

since, its increased by 200%

⇛radius increased 3 times

i.e. 3r

We know that,

volume of sphere = 4/3 × πr³

volume of sphere when radius is increased by 200%

$= \frac{4}{3} \pi {(3r)}^{3} \\ = \frac{4}{3} \pi \times 27 {r}^{3}$

The increase in volume is given by

$\frac{ \frac{4}{3}\pi (27 {r}^{3}) - \frac{4}{3} \pi {r}^{3} }{ \frac{4}{3} \pi {r}^{3} } \times 100 \\ = \frac{ \frac{4}{3} \pi {r}^{3}(27 - 1) }{ \frac{4}{3} \pi {r}^{3} } \times 100 \\ = 26 \times 100 \\ = 2600\%$

Answer 2

Answer:

$2600\%$

is correct answer

Step-by-step explanation:

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