Question

question :-

The ratio in which the x-axis divides the line segment joining the point (3,2) and (-8,4) is ?

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Answer 1

$\underline{\underline{\huge{\blue{\tt{\textbf Answer :-}}}}}$

• The ratio in which the x-axis divides the line segment joining the point (3,2) and (-8,4) is 1:2

$\underline{\underline{\huge{\red{\tt{\textbf Explanation :-}}}}}$

$a = (x _{1}, y_{1}) = (3,2) \\ b = (x _{2} ,y_{2}) =( - 8,4)$

We are given thatx axis divides the line ab,

so y=0

So, the point at which x axis cut the line ab =(x,0)

Let the ratio be k:1

(x,y)(x,0)

we will use section formula:-

$x = \frac{mx_{2} + nx_{1}}{m + n } \\ y = \frac{my_{2} + ny_{1}}{m + n }$

substitute the value.

m:n=k:1

$x = \frac{k( - 8) + 1(3)}{k \ + 1 } \\ x = \frac{ - 8k + 3}{k + 1}$ and

$y = \frac{my_{2} + ny_{1}}{k + 1} \\ 0 = \frac{k(6) + 1( - 3)}{k + 1} \\ 0 = \frac{6k - 3}{k + 1} \\ 6k - 3 = 0 \\ 6k = 3 \\ k = \frac{3}{6} \\ k = \frac{1}{2}$

Hence,

The ratio in which the x-axis divides the line segment joining the point (3,2) and (-8,4) is 1:2

Answer 2

Question: please you give yourself answer