Question

Question
➝ The sum of the 4th and 8th of an AP is 24 and the sum of the 6th and 10th term is 44. Find the first three terms of the AP.

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Answer 1

Answer:

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Answer 2

Answer with explanation :-

Given that the sum of the 4th and 8th term of an AP is 24.

➝ a + 3d + a + 7d = 24

➝ 2a + 10d = 24. ...(i)

Also the sum of the 6th and 10th term is 44

➝ a + 5d + a + 9d = 44

➝ 2a + 14d = 44. ...(ii)

Subtract equation (I) from equation (ii) , we get:

4d = 20

➝ d = 5

Substituting d = 5 in equation (i) , we have

2a + 10d = 24

➝ 2a + 10 (5) = 24

➝ 2a + 50 = 24

➝ 2a = -26

➝ a = -13

Hence , first term of given A.P. is -13 and common difference is 5.