Question

Question :-

The value of x² + 2 $\sf{\sqrt{3x + 3}}$ is = ?

Options :-
$a)x + \sqrt{3} \\ b) {(x + 3)}^{2} \\ c) {(x + \sqrt{3}) }^{2} \\ d){(x - \sqrt{3}) }^{2}$
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Answer 1

Answer:

$(x - \sqrt[2]{3} ) ^{2}$

Step-by-step explanation:

By expanding we get x² + 2$\sqrt{3x + 3}$

Answer 2

$\huge \bold \orange{ᴀɴsᴡᴇʀ }$

No one is helping me (◣_◢)!!