Question

★ Question:-

There are two numbers such that the sum of the numbers is 48 and their difference is 8 find the difference of their squares ​

Answer 1

Solution:-

Given that the sum and the difference of two numbers is 48 and 8, respectively.

Let the numbers be x and y.

So, according to the question,

x + y = 48 ... (1)

x - y = 8 ... (2)

Now, let's add (1) and (2).

x + x + y - y = 48 + 8

2x = 56

x = 28

Substitute the value of x in (1) in order to get the value of y.

x + y = 48

28 + y = 48

y = 48 - 28

y = 20

We are asked to find the difference of the squares of x and y. So,

→ (28)² - (20)²

→ 784 - 400

→ 384

The difference of the squares of x and y is 384.