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Given molarity and volume ..
you can find out the moles of H2SO4 -
= 0.3×200 = 60 millimoles
now clearly 2 moles of NaOH are required for 1 mole of H2SO4.
So moles of NaOH required = 120 millimoles
hence mass = 120 × 40
= 4800 mg
= 4.8g
Hope it helps you..
just let me know if you have any dóubt
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